NOTE This device is not compatible with Zigbee Home Assistant. Please use Tuya or Smart Life APP. It is not compatible with other APPs. NEW ARRIVAL ZigBee Smart Energy Meter with Clamp 80A Do you have a Tuya Zigbee Gateway? You need to prepare a Tuya Zigbee Gateway as Hub for this device, because it can not receive 2.4G wifi signals directly. Specifications From the APP You Can Read: Hourly Elec. (KWh) Weekly Elec. (KWh) on 'Smart' Page Daily Elec. (KWh), on 'Smart' Page Monthly Elec. (KWh) on 'Smart' Page Current Ele(mA), Current Power(W), Current Voltage(V), Please note it's not bidirectional meter, it can only measure the consumed power. and only show positive data on App. Technical data: Rated Voltage:100-240V AC 50/60Hz Measurable Current Range: 0.2A-80A Wireless Protocol: ZigBee Ambient Temperature Range:-10°C ~ 55°C App Real Time Monitor Energy Consumed KWh. Voltage, Current, and Power, also can Monitor Device Working Status Electricity and Cost Statistic You can view daily , weekly , monthly, KWh and Electricity Costs Consumed .During the Period in App Automation , It allows to make a Scene for this device working with other tuya devices Set Automation for the Measured Device , For example, If Power or Current Is over the Value, then other tuya device starts to work . Automation. send a notification Non-connect to Be Safe, Easy and Safe to Install No need to change the wires, Just put the wire into the clamp, then it can measure, very easy. Small Size Module , Easy to Install We guarantee good quality, every product will be tested before delivery. Not before Order Q&A Q : After I configure it with App , why App shows 'shutdown' ? A : Only if you put a device's wire (either live wire or neutral wire, not both) in the clamp, and turn on the device, then the clamp can sense the current, and App will show it is working Q : I suppose P= U*I, why the value shows on App is not correct ? A : Please consider the cos(Φ). Because As resistances do not produce any phasor difference (phase shift) between voltage and current waveforms, all the useful power is delivered directly to the resistance and converted to heat, light and work. Then the power consumed by a resistance is real power which is fundamentally the circuits average power. To find the corresponding value of the real power the rms voltage and current values are multiplied by the cosine of the phase angle, Φ as shown. Best Regards

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